1x^2-3y^2=

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Solution for 1x^2-3y^2= equation: 


Simplifying
1x2 + -3y2 = 0

Solving
1x2 + -3y2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '3y2' to each side of the equation.
1x2 + -3y2 + 3y2 = 0 + 3y2

Combine like terms: -3y2 + 3y2 = 0
1x2 + 0 = 0 + 3y2
1x2 = 0 + 3y2
Remove the zero:
1x2 = 3y2

Divide each side by '1'.
x2 = 3y2

Simplifying
x2 = 3y2

Take the square root of each side:
x = {-1.732050808y, 1.732050808y}

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